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What is the work-energy theorem?
Exam-ready answer
The work-energy theorem states that the change in kinetic energy of a particle is equal to the work done on it by the net force: K_f − K_i = W. Here kinetic energy K = ½mv². If the net force does positive work, the body speeds up; if it does negative work, the body slows down.
Explanation
Start with the equation of motion for constant acceleration: v² − u² = 2as, where u is the initial speed, v the final speed and s the displacement. Multiply both sides by m/2. This gives ½mv² − ½mu² = mas. By Newton's second law, ma is the net force F, so the right-hand side becomes Fs, which is the work done by the net force over the displacement s.
So ½mv² − ½mu² = Fs, or K_f − K_i = W. The quantity ½mv² is the kinetic energy of the body, a scalar measured in joules (J). The theorem also holds for a variable force, where the work is found by integrating F dx over the path. It is the integral form of Newton's second law and links force and displacement directly to the change in speed.
Example: a moving car brakes to a stop. The friction force acts opposite to the displacement, so it does negative work. That negative work equals the loss of the car's kinetic energy. Similarly, when a raindrop falls, gravity does positive work and air resistance does negative work; the net work done by both forces equals the change in the drop's kinetic energy.
Points to remember
- Statement: the change in kinetic energy of a particle equals the work done on it by the net force.
- Formula: K_f − K_i = W, where K = ½mv².
- Proof uses v² − u² = 2as multiplied by m/2, with F = ma.
- Work and kinetic energy are scalars; SI unit is the joule (1 J = 1 N m).
- Positive net work increases speed; negative net work (e.g. friction) decreases speed.
Exam tip
Show the three-line proof: v² − u² = 2as, multiply by m/2, replace ma by F. Then write K_f − K_i = W in a box and give the SI unit, joule.
Questions students also ask
What is the work done by a force?
Does the theorem work for a variable force?
Why does a body moving in a circle at constant speed keep its kinetic energy?
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